JavaScript array_diff_ukey
Returns the entries of arr1 that have keys which are not present in any of the others arguments. User supplied function is used for comparing the keys. This function is like array_udiff() but works on the keys instead of the values. The associativity is preserved.
1 2 3 4 56 7 8 9 1011 12 13 14 1516 17 18 19 2021 22 23 24 2526 27 28 29 3031 | function array_diff_ukey () { // Returns the entries of arr1 that have keys which are not present in any of the others arguments. User supplied function is used for comparing the keys. This function is like array_udiff() but works on the keys instead of the values. The associativity is preserved. // // version: 1008.1718 // discuss at: http://phpjs.org/functions/array_diff_ukey // + original by: Brett Zamir (http://brett-zamir.me) // * example 1: $array1 = {blue: 1, red: 2, green: 3, purple: 4} // * example 1: $array2 = {green: 5, blue: 6, yellow: 7, cyan: 8} // * example 1: array_diff_ukey($array1, $array2, function (key1, key2){ return (key1 == key2 ? 0 : (key1 > key2 ? 1 : -1)); }); // * returns 1: {red: 2, purple: 4} var arr1 = arguments[0], retArr = {}, cb = arguments[arguments.length-1]; var arr = {}, i = 1, k1 = '', k = ''; cb = (typeof cb === 'string') ? this.window[cb] : (cb instanceof Array) ? this.window[cb[0]][cb[1]] : cb; arr1keys: for (k1 in arr1) { for (i=1; i < arguments.length-1; i++) { arr = arguments[i]; for (k in arr) { if (cb(k, k1) === 0) { // If it reaches here, it was found in at least one array, so try next value continue arr1keys; } } retArr[k1] = arr1[k1]; } } return retArr;} |
Examples
Running
1 2 3 | $array1 = {blue: 1, red: 2, green: 3, purple: 4} $array2 = {green: 5, blue: 6, yellow: 7, cyan: 8} array_diff_ukey($array1, $array2, function (key1, key2){ return (key1 == key2 ? 0 : (key1 > key2 ? 1 : -1)); }); |
Should return
1 | {red: 2, purple: 4} |
Dependencies
No dependencies, you can use this function standalone.
Open syntax issues
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Authors
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