JavaScript array_filter
Filters elements from the array via the callback.
1 2 3 4 56 7 8 9 1011 12 13 14 1516 17 18 19 2021 22 23 24 | function array_filter (arr, func) { // Filters elements from the array via the callback. // // version: 909.322 // discuss at: http://phpjs.org/functions/array_filter // + original by: Brett Zamir (http://brett-zamir.me) // % note 1: Takes a function as an argument, not a function's name // * example 1: var odd = function (num) {return (num & 1);}; // * example 1: array_filter({"a": 1, "b": 2, "c": 3, "d": 4, "e": 5}, odd); // * returns 1: {"a": 1, "c": 3, "e": 5} // * example 2: var even = function (num) {return (!(num & 1));} // * example 2: array_filter([6, 7, 8, 9, 10, 11, 12], even); // * returns 2: {0: 6, 2: 8, 4: 10, 6: 12} var retObj = {}, k; for (k in arr) { if (func(arr[k])) { retObj[k] = arr[k]; } } return retObj; } |
Examples
» Example 1
Running
1 2 | var odd = function (num) {return (num & 1);}; array_filter({"a": 1, "b": 2, "c": 3, "d": 4, "e": 5}, odd); |
Should return
1 | {"a": 1, "c": 3, "e": 5} |
» Example 2
Running
1 2 | var even = function (num) {return (!(num & 1));} array_filter([6, 7, 8, 9, 10, 11, 12], even); |
Should return
1 | {0: 6, 2: 8, 4: 10, 6: 12} |
Dependencies
No dependencies, you can use this function standalone.
Open syntax issues
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Authors
Thanks to the following developers, you get to have array_filter goodness in JavaScript.
@J: Sorry, no difference. If you set a key on a JS array, it will fill in the gaps with 'undefined'.
Try this with our function:
var arr = array_filter2([3, 4, 5, 6], function (n) {return n >= 5;});
alert(arr.length); // Should be 2, but is 4
Yours gives four, while ours doesn't pretend to be an array (there's no length at all), so it is not confusing.
Oops, I meant to put retObj.length to omit the null ones..
Not sure if that makes any diff..
1 2 3 | if(!this.is_null(arr[i])){ retObj[retObj.length] = arr[i]; } |
@J.: While I know it's definitely tempting to try it that way, a problem arises when the preserved filtered results are not all sequential at the beginning of the array (probably most times); the keys will either end up not being preserved (as they are in PHP), or, as in your code, we'd end up making an array with "undefined" values throughout in place of missing values and which showed a size equal to the original array instead of the length of filter-positive values (as most people would probably want it).
In a number of functions we really have to return an array, though there may be a few which could be adapted to try to return a genuine array where possible. But as far as array_filter, the cases where this would be valid (positive results all sequential at the beginning) would be uncommon, and probably confusing if we didn't follow a uniform policy (unless, again, the results would be consistent).
php handles both array and object, unfortunately JS does not distinguish indexed array and hashed array object...
array_filter in php handles both types and returns type intacted.. Can we add type check like below?
1 2 3 4 56 7 8 9 1011 12 13 14 1516 17 18 19 2021 22 23 24 2526 27 28 29 3031 32 33 34 3536 37 38 39 40 | array_filter: function (arr, func) { var retObj, k, type = 'array'; func_set = 0; if(this.isset(func)) func_set = 1; // Check for 'length' if(arr.length === undefined){ type = 'hashed_array'; } if(type == 'hashed_array'){ retObj = {}; for (k in arr) { if(func_set){ if (func(arr[k])) { retObj[k] = arr[k]; } }else{ if(this.is_null(arr[k])) continue; retObj[k] = arr[k]; } } }else{ retObj = []; for(i=0;i<arr.length;++i){ if(func_set){ if (func(arr[i])) { retObj[i] = arr[i]; } }else{ if(this.is_null(arr[i])) continue; retObj[i] = arr[i]; } } } return retObj; } |


Brett Zamir
18 Aug '09