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function array_intersect () {
    // Returns the entries of arr1 that have values which are present in all the other arguments  
    // 
    // version: 909.322
    // discuss at: http://phpjs.org/functions/array_intersect    // +   original by: Brett Zamir (http://brett-zamir.me)
    // %        note 1: These only output associative arrays (would need to be
    // %        note 1: all numeric and counting from zero to be numeric)
    // *     example 1: $array1 = {'a' : 'green', 0:'red', 1: 'blue'};
    // *     example 1: $array2 = {'b' : 'green', 0:'yellow', 1:'red'};    // *     example 1: $array3 = ['green', 'red'];
    // *     example 1: $result = array_intersect($array1, $array2, $array3);
    // *     returns 1: {0: 'red', a: 'green'}
    var arr1 = arguments[0], retArr = {};
    var k1 = '', arr = {}, i = 0, k = '';    
    arr1keys:
    for (k1 in arr1) {
        arrs:
        for (i=1; i < arguments.length; i++) {            arr = arguments[i];
            for (k in arr) {
                if (arr[k] === arr1[k1]) {
                    if (i === arguments.length-1) {
                        retArr[k1] = arr1[k1];                    }
                    // If the innermost loop always leads at least once to an equal value, continue the loop until done
                    continue arrs;
                }
            }            // If it reaches here, it wasn't found in at least one array, so try next value
            continue arr1keys;
        }
    }
     return retArr;
}

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$array1 = {'a' : 'green', 0:'red', 1: 'blue'};
$array2 = {'b' : 'green', 0:'yellow', 1:'red'};
$array3 = ['green', 'red'];
$result = array_intersect($array1, $array2, $array3);

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{0: 'red', a: 'green'}