JavaScript array_intersect_ukey
Returns the entries of arr1 that have keys which are present in all the other arguments. Kind of equivalent to array_diff(array_keys($arr1), array_keys($arr2)[,array_keys(...)]). The comparison of the keys is performed by a user supplied function. Equivalent of array_intersect_uassoc() but does not do compare of the data.
1 2 3 4 56 7 8 9 1011 12 13 14 1516 17 18 19 2021 22 23 24 2526 27 28 29 3031 32 33 34 3536 37 38 39 40 | function array_intersect_ukey (arr1) { // Returns the entries of arr1 that have keys which are present in all the other arguments. Kind of equivalent to array_diff(array_keys($arr1), array_keys($arr2)[,array_keys(...)]). The comparison of the keys is performed by a user supplied function. Equivalent of array_intersect_uassoc() but does not do compare of the data. // // version: 1109.2015 // discuss at: http://phpjs.org/functions/array_intersect_ukey // + original by: Brett Zamir (http://brett-zamir.me) // * example 1: $array1 = {blue: 1, red: 2, green: 3, purple: 4} // * example 1: $array2 = {green: 5, blue: 6, yellow: 7, cyan: 8} // * example 1: array_intersect_ukey ($array1, $array2, function (key1, key2){ return (key1 == key2 ? 0 : (key1 > key2 ? 1 : -1)); }); // * returns 1: {blue: 1, green: 3} var retArr = {}, arglm1 = arguments.length - 1, arglm2 = arglm1 - 1, cb = arguments[arglm1], k1 = '', i = 1, arr = {}, k = ''; cb = (typeof cb === 'string') ? this.window[cb] : (Object.prototype.toString.call(cb) === '[object Array]') ? this.window[cb[0]][cb[1]] : cb; arr1keys: for (k1 in arr1) { arrs: for (i = 1; i < arglm1; i++) { arr = arguments[i]; for (k in arr) { if (cb(k, k1) === 0) { if (i === arglm2) { retArr[k1] = arr1[k1]; } // If the innermost loop always leads at least once to an equal value, continue the loop until done continue arrs; } } // If it reaches here, it wasn't found in at least one array, so try next value continue arr1keys; } } return retArr; } |
Examples
Running
1 2 3 | $array1 = {blue: 1, red: 2, green: 3, purple: 4} $array2 = {green: 5, blue: 6, yellow: 7, cyan: 8} array_intersect_ukey ($array1, $array2, function (key1, key2){ return (key1 == key2 ? 0 : (key1 > key2 ? 1 : -1)); }); |
Should return
1 | {blue: 1, green: 3} |
Dependencies
No dependencies, you can use this function standalone.
Open syntax issues
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Authors
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