JavaScript is_finite

Returns whether argument is finite

function is_finite (val) {
    // Returns whether argument is finite  
    // 
    // version: 1109.2015
    // discuss at: http://phpjs.org/functions/is_finite    // +   original by: Onno Marsman
    // *     example 1: is_finite(Infinity);
    // *     returns 1: false
    // *     example 2: is_finite(-Infinity);
    // *     returns 2: false    // *     example 3: is_finite(0);
    // *     returns 3: true
    var warningType = '';
 
    if (val === Infinity || val === -Infinity) {        return false;
    }
 
    //Some warnings for maximum PHP compatibility
    if (typeof val == 'object') {        warningType = (Object.prototype.toString.call(val) === '[object Array]' ? 'array' : 'object');
    } else if (typeof val == 'string' && !val.match(/^[\+\-]?\d/)) {
        //simulate PHP's behaviour: '-9a' doesn't give a warning, but 'a9' does.
        warningType = 'string';
    }    if (warningType) {
        throw new Error('Warning: is_finite() expects parameter 1 to be double, ' + warningType + ' given');
    }
 
    return true;}

external links: original PHP docs | raw js source

Examples

» Example 1

Running

1	is_finite(Infinity);

Should return

false

» Example 2

Running

1	is_finite(-Infinity);

Should return

false

Dependencies

No dependencies, you can use this function standalone.

Open syntax issues

php.js uses JsLint to help us keep our code consistent and prevent some common bugs.

Eventually we want all code to pass or at least take into consideration most fixes suggested by JsLint, following this JsLint configuration we’ve decided on.

Authors

Thanks to the following developers, you get to have is_finite goodness in JavaScript.

Onno Marsman ( original )

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