JavaScript is_resource

Returns true if variable is a resource

function is_resource (handle) {
    // Returns true if variable is a resource  
    // 
    // version: 910.813
    // discuss at: http://phpjs.org/functions/is_resource    // +   original by: Brett Zamir (http://brett-zamir.me)
    // +   improved by: Luis Salazar (http://www.freaky-media.com/)
    // *     example 1: is_resource('a');
    // *     returns 1: false
    var getFuncName = function (fn) {        var name = (/\W*function\s+([\w\$]+)\s*\(/).exec(fn);
        if (!name) {
            return '(Anonymous)';
        }
        return name[1];    };
    return !(!handle || typeof handle !== 'object' || !handle.constructor || getFuncName(handle.constructor) !== 'PHPJS_Resource');
}

external links: original PHP docs | raw js source

Examples

Running

1	is_resource('a');

Should return

false

Dependencies

No dependencies, you can use this function standalone.

Open syntax issues

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Eventually we want all code to pass or at least take into consideration most fixes suggested by JsLint, following this JsLint configuration we’ve decided on.